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Review Question - QID 2985

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QID 2985 (Type "2985" in App Search)
Figure A represents a free body diagram of the hip of a patient standing on the right leg. The forces and distances are labeled on the diagram and the resulting hip joint force (J) = 1800N. What is the resultant value for J when the acetabular component is medialized given the new distances shown in Figure B?
  • A
  • B

1000N

5%

207/3801

1200N

64%

2442/3801

1800N

8%

303/3801

2200N

10%

389/3801

3600N

10%

395/3801

  • A
  • B

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The new joint force (J) calculated is 1200N as shown in Illustration A. The joint force decreases as the acetabular component is moved medial. This is a result of decreasing abductor tension as the acetabular component is medialized (Distance B is 50mm instead of the initial 100mm). Mechanical equilibrium is when the sums of all forces and moments equal zero [(AT x A) - (5/6BW)x B)) = 0]. Free body diagrams show the locations and directions of all forces and moments acting on a body. The body and the left leg weigh 5/6 x total body weight (BW) in a right-sided single leg stance as given in this example.

The article by Johnston et al created a mathematical hip model that found that the loads on the hip were lowered by placing the center of the acetabulum as far medially, inferiorly, and anteriorly as possible.

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